How does it work?
When you pull a rod, its atoms move apart, and the bonds between them act like tiny springs. To compare thick and thin rods, long and short, engineers calculate stress (force per unit of cross-sectional area) and strain (relative change in length):
σ = FAε = ΔLL₀σ = E·εΔL = FLEA1 MPa = 1 N/mm² · Young's modulus E of steel ≈ 200 GPa = 200,000 MPa · Hooke's law holds only in the elastic range
So a rod is a spring with stiffness k = EA/L. A steel rod Ø1 cm and 1 m long has k ≈ 15.7 kN/mm: a car of about 1.5 t will stretch it by less than a millimeter. Above the yield strength, the metal flows and stays permanently elongated; the highest point of the curve is the tensile strength Rm, after which a neck forms and the sample breaks.
Trusses
Truss members are pin-jointed, so they can only be in tension or compression. At every node the forces must balance. For n nodes that's 2n equations; the computer assembles them into a system K·u = F and solves it by Gaussian elimination. A pin-jointed triangle can't change shape without changing the lengths of its sides — a square can. A plane truss is rigid and statically determinate when the number of members is m = 2n − 3 (and the members are well placed).
Beams
A bent beam shortens at the top (compression) and lengthens at the bottom (tension); in the middle lies the neutral axis. Stress grows linearly with distance from it, and stiffness comes from the cross-section's moment of inertia I — material far from the axis does the most work. Hence the I-beam: two thick flanges far from the axis and a thin web.
σ = M·yIIrectangle = bh³12wmax = PL³48EIlast formula: force at the middle of a simply supported beam · the same rectangle on edge is (h/b)² times stiffer than flat
Buckling and arches
A slender rod in compression stays straight up to a certain force, then suddenly bows sideways. Leonhard Euler derived this force in 1744:
Pcr = π²EI(KL)²λ = KLi, i = √(I/A)K = 1 (pinned), 2 (cantilever), ≈ 0.7 (fixed + pinned), 0.5 (both fixed) · a rod twice as long buckles at a quarter of the force
An arch shaped like an inverted chain contains only compression — which is why stone and brick are enough.
Scale, stress concentration and fatigue
When scaled up ×k, weight grows as k³ and cross-section as k², so stress grows as k. Near a hole, stress locally rises Kt times (for a round hole in a wide plate Kt = 3, for an elliptical one 1 + 2a/b), and sharp corners are the worst. Repeated loading, even below the yield strength, creates microcracks in such spots that grow with every cycle — that's metal fatigue.
Simplifications: materials are homogeneous; the tensile curves are smooth approximations of typical values. The truss has ideal pin joints and members made of steel tubes (E = 200 GPa, Re = 355 MPa); the truck is a single point load; we ignore the bridge's own weight and apply no safety factors. Beams: linear Euler–Bernoulli theory (small deflections), without self-weight or lateral-torsional buckling. Reinforced concrete: a simplified model that cracks at 3 MPa with capacity from the steel. Buckling: Euler's formula for an elastic rod with a small initial curvature. The chain is a simple simulation of links. Stress map: linear FEM (plane stress, about 3–4 thousand elements on a quarter of the plate). The paper-clip fatigue curve is illustrative. Deflections in the drawings are heavily exaggerated — the scale is always shown.
See also